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y^2-24y=441
We move all terms to the left:
y^2-24y-(441)=0
a = 1; b = -24; c = -441;
Δ = b2-4ac
Δ = -242-4·1·(-441)
Δ = 2340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2340}=\sqrt{36*65}=\sqrt{36}*\sqrt{65}=6\sqrt{65}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-6\sqrt{65}}{2*1}=\frac{24-6\sqrt{65}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+6\sqrt{65}}{2*1}=\frac{24+6\sqrt{65}}{2} $
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